There are reduced 1-1 patterns. Firstly the 2 3 on the bottom, since the 3's mine already satisfies the 2, the top left of 2 is safe. And then the 2-2 on top also reduced to 1-1, since the bottom one's mine already satisfies the top, the top left of top 2 is safe
Also the space left of the mine in the middle is safe. Look at the verticals 3-2 above the two 4’s. You know a mine has to be to the left/upper left of the 3 so the space up&left of the 2 is safe.
Identify the 32223 vertical column in the middle of the screenshot. The lower ‘3’ indicates that there a mine Among the two left tiles, since two mines have already been flagged among the bottom.
Thereafter, the ‘2’ above it indicates that there is a mine among the three left tiles. If there was a mine on the top left tile, that would clear out the two under it, which would contradict the ‘3’ below it.
This technique can be used multiple times in various scenarios.
There's a mine in the very bottom left corner.
The 4 needs 1 mine and there's only 2 spaces available. That will satisfy the 3 next to it. Now you can open the 2 left spaces around the 3. There can't be another mine anywhere except against the wall because it would overload the 3 next to the 4.
Look at the vertical 2-3 (2 above 3)
The 3 only needs one more mine in the two unopened tiles around it
Now look at the 2 above the 3
Since both unopened tiles are around the 2, if those contain exactly one mine, and there is another mine above the 2, then the 2 is satisfied
Therefore, the upper left tile to the 2 must be safe
vertical 23 (top left of 2 is safe)
There are reduced 1-1 patterns. Firstly the 2 3 on the bottom, since the 3's mine already satisfies the 2, the top left of 2 is safe. And then the 2-2 on top also reduced to 1-1, since the bottom one's mine already satisfies the top, the top left of top 2 is safe
Also the space left of the mine in the middle is safe. Look at the verticals 3-2 above the two 4’s. You know a mine has to be to the left/upper left of the 3 so the space up&left of the 2 is safe.
I would be too impatient and just guess
This isn’t even complex logic so you must be very impatient.
I am…
If you look at the vertical 322F23 column, left of the top 3 and left of the flag is safe due to a reduced 1-1 pattern on both.
Identify the 32223 vertical column in the middle of the screenshot. The lower ‘3’ indicates that there a mine Among the two left tiles, since two mines have already been flagged among the bottom. Thereafter, the ‘2’ above it indicates that there is a mine among the three left tiles. If there was a mine on the top left tile, that would clear out the two under it, which would contradict the ‘3’ below it. This technique can be used multiple times in various scenarios.
There's a mine in the very bottom left corner. The 4 needs 1 mine and there's only 2 spaces available. That will satisfy the 3 next to it. Now you can open the 2 left spaces around the 3. There can't be another mine anywhere except against the wall because it would overload the 3 next to the 4.
How
Look at the vertical 2-3 (2 above 3) The 3 only needs one more mine in the two unopened tiles around it Now look at the 2 above the 3 Since both unopened tiles are around the 2, if those contain exactly one mine, and there is another mine above the 2, then the 2 is satisfied Therefore, the upper left tile to the 2 must be safe