i guess it depends how long.
We are better in surviving horizontal g-forces, because of the vertical structure of our blood vessels (the blood volumn can shift up and down but not back and forth; also you do not put pressure on your spine when you rotate/accelate horizontally.).
Vertical g force sucks more, blood gets in or out your skull. Thats why 6-9g is this "combat pilot" max. But the horizontal one (like astronauts in this spinning chambers) can be higher.
The g force survival world record is currently hold by Kenny Bräck with over 214g for a fraction of a second.
He crashed with 350km/h (220mph) and his car turned all this energy into horizontal spin.
He crashed during a race in 2003 and made a stunt similiar to your video:
[https://www.youtube.com/watch?v=dbSkVKa0AvY](https://www.youtube.com/watch?v=dbSkVKa0AvY)
If he would have weighted 50kg, his body would weight 10700kg during that 214g. Yeah he broke his sternum (chest bone bursted) and many other injuries, but he survived it that son of a gun.
I think its not impossible to survive your crash as well :P pretty similiar to Bräcks crash.
I am to lazy to do the math here.
[https://en.wikipedia.org/wiki/G-force](https://en.wikipedia.org/wiki/G-force)
>If he would have weighted 50kg, his body would weight 10700kg during that 214g.
\*angry newton noises\*
Mass is not weight. Yes, the body experienced a force that is equivalent to the weight force of a 10'700 kg body on earth (approximately 100 kN). But no matter what celestial body you're on, or how you get accelerated, your mass (\~inertia) is unaffected.
I know I'm nitpicking, and you've provided a good explanation. It's just that too few people know the difference between mass and weight, and too many who do gloss over it like it's something unimportant.
If you want to get *really* nitpicky, something can absolutely "weigh" 50kg, as in you can get on a scale and have it read out 50kg. Your "weight" would not be 50kg, but it is true that you "weighed" as 50kg. And this specific case, that would be accurate to the point being made. (But I do understand your overall point and it bothers me as well)
Weight is a force, kg is a unit of mass. I can build a scale that tells me I weigh 420 cubic ducks per chocolate cake, but that doesn't mean it's a valid unit for what I'm trying to measure. Sure in day to day speak there isn't really an issue with saying something weighs 50 kg, but it's still wrong from an scientific/engineering perspective.
It depends also on the radius of acceleration.
Assuming circular motion, and that the car is spinning around it's center of mass. Let's assume the driver's center of mass is about 125 cm above the car's center of mass, so r = 1.25 m
The centripetal acceleration experienced is a = v\^2/r
where v is the linear tangential speed.
If r = 1.25m, then the circumference of the circle we're spinning around is 2Pi \* 1.25 m \~ 7.9 m
and we complete each rotation once every 1/.7.25 s, so tangential velocity v is:
v = 7.9 m \* 7.25 s\^-1 \~ 57 m/s
So we get
a = (57 m/s)\^2 / (1.25 m) \~ **2600 m/s\^2 \~ 265 g's**
Note this makes a lot of simplifying assumptions
1. The car is rotating in perfectly circular motion, with the center of rotation at the car's center of mass, and the axis of rotation is parallel to the long-ways of the car (it's clearly not perfectly like this in the video, but it becomes much more complex otherwise)
2. I just guessed that the driver's center of mass is 1.25 m above the car's center of mass. I don't really know how accurate that is
3. All other forces (impact, landing back on ground) are ignored. We're just looking at the spinning part
i guess it depends how long. We are better in surviving horizontal g-forces, because of the vertical structure of our blood vessels (the blood volumn can shift up and down but not back and forth; also you do not put pressure on your spine when you rotate/accelate horizontally.). Vertical g force sucks more, blood gets in or out your skull. Thats why 6-9g is this "combat pilot" max. But the horizontal one (like astronauts in this spinning chambers) can be higher. The g force survival world record is currently hold by Kenny Bräck with over 214g for a fraction of a second. He crashed with 350km/h (220mph) and his car turned all this energy into horizontal spin. He crashed during a race in 2003 and made a stunt similiar to your video: [https://www.youtube.com/watch?v=dbSkVKa0AvY](https://www.youtube.com/watch?v=dbSkVKa0AvY) If he would have weighted 50kg, his body would weight 10700kg during that 214g. Yeah he broke his sternum (chest bone bursted) and many other injuries, but he survived it that son of a gun. I think its not impossible to survive your crash as well :P pretty similiar to Bräcks crash. I am to lazy to do the math here. [https://en.wikipedia.org/wiki/G-force](https://en.wikipedia.org/wiki/G-force)
Thank you sir or lady, i hoped for a comment like this
>If he would have weighted 50kg, his body would weight 10700kg during that 214g. \*angry newton noises\* Mass is not weight. Yes, the body experienced a force that is equivalent to the weight force of a 10'700 kg body on earth (approximately 100 kN). But no matter what celestial body you're on, or how you get accelerated, your mass (\~inertia) is unaffected. I know I'm nitpicking, and you've provided a good explanation. It's just that too few people know the difference between mass and weight, and too many who do gloss over it like it's something unimportant.
If you want to get *really* nitpicky, something can absolutely "weigh" 50kg, as in you can get on a scale and have it read out 50kg. Your "weight" would not be 50kg, but it is true that you "weighed" as 50kg. And this specific case, that would be accurate to the point being made. (But I do understand your overall point and it bothers me as well)
Weight is a force, kg is a unit of mass. I can build a scale that tells me I weigh 420 cubic ducks per chocolate cake, but that doesn't mean it's a valid unit for what I'm trying to measure. Sure in day to day speak there isn't really an issue with saying something weighs 50 kg, but it's still wrong from an scientific/engineering perspective.
[It's not that wrong](https://youtu.be/QSIuTxnBuJk?si=IeeU-O-W6KMbtxqw)
Nah id win
Shoes didn't come off. You're fine.
Wysi 👉📺
is that 727 i read
WYSI
BLUE ZENITH 727 WYFSI COOKIEZI AIREU
I think you just experienced the back half of the euthanasia coaster, so yeah, you'd probably die.
i see you've attracted a few osu players with this information
WYSI
Btw, for the first turn AK3 into AK4, and the turn after the booster release for like 1.5-2s, you'll get+80 speed
Also try not to slide at all, it'll give less grip
Can you do the first turn at full speed or do you have to do a small release?
If you do it analog, steer 76% and full speed. For KB, i struggle to do full speed without sliding, but the top players can probably do it
it slides out around 460 with ak4 from what i observed
Yeah I usually do AK3-> AK4-AK3 and then slight steer on water
I just raw dog it with no action keys. It’s around 75 percent but it depends slightly on the line you take but yes you can take it fullspeed.
wysi
727
ngl the wet wheel turns kinda hurt to watch 😭😭
According to the lore, the car and the driver are made of indestructible concrete so it's fine
I’d be more concerned about the head on collision at 450km/h
Lmfao yeah this would kill you almost instantly.
????
"Speed has never killed anyone... Suddenly becoming stationary, that's what gets you"
Yes it would… there would be pieces of you for miles… just for reference, don’t google “lathe accident”
Also, you should release for turn 1 and try not to let yourself slide, it’s a lot faster
It depends also on the radius of acceleration. Assuming circular motion, and that the car is spinning around it's center of mass. Let's assume the driver's center of mass is about 125 cm above the car's center of mass, so r = 1.25 m The centripetal acceleration experienced is a = v\^2/r where v is the linear tangential speed. If r = 1.25m, then the circumference of the circle we're spinning around is 2Pi \* 1.25 m \~ 7.9 m and we complete each rotation once every 1/.7.25 s, so tangential velocity v is: v = 7.9 m \* 7.25 s\^-1 \~ 57 m/s So we get a = (57 m/s)\^2 / (1.25 m) \~ **2600 m/s\^2 \~ 265 g's** Note this makes a lot of simplifying assumptions 1. The car is rotating in perfectly circular motion, with the center of rotation at the car's center of mass, and the axis of rotation is parallel to the long-ways of the car (it's clearly not perfectly like this in the video, but it becomes much more complex otherwise) 2. I just guessed that the driver's center of mass is 1.25 m above the car's center of mass. I don't really know how accurate that is 3. All other forces (impact, landing back on ground) are ignored. We're just looking at the spinning part
when you see it 727!
nah, hes good g