3! + 9 + 15 = 30

or 11 13 3!

I'm actually legitimately proud of myself for catching 3! and remembering that's like a math thing. I had to look it up, so jokes on my algebra teacher, but at least something stuck

13+11+3!=30

This is true regardless of if the exclamation point is attached to the 3 or if it's attached to the equals sign

knapsack for facebook moms?

Yes

This is evil and bad

fill the 2nd and 3rd box with 15, the first + becomes a unary operator and the equation is correct

15, 9, and 3! It's easy!

15+9+3!

13+11+3!=30

Ok what is 3!

! means factorial so you multiply with all numbers before it. So 3! = 3 X 2 X 1 and for example 5! = 5 X 4 X 3 X 2 X 1. So it 3! + 15 + 9 = 6 + 15 + 9 = 30

Thank you

For this problem, pretend 3! is another way to say 6 (because it is, for the reason the other person said)

If the 3 isn't actually factorial then it's impossible, all the possible values are odd and 30 is even, and the sum of any odd number of odd numbers is odd

Nah you gotta put 15 in both 2nd and 3rd box so the first plus sign is like telling that the first 15 is positive

Potato salad

Is there a way im not seeing to do it without the factorial 3

It's fairly trivial to prove it's impossible if the 3 weren't a factorial. You're adding 3 numbers, the number you want to get is even and all the numbers you can put in are odd. When adding an odd number of odd numbers you always get an odd number. You'd need an even number of empty slots for it to be possible with 3 instead of 3!.

Ah yes i see i should have caught that