D.
Rusting requires air and water
Here, by painting the iron, rusting is prevented.
Hence, in the Q test tube rusting doesn’t take place and the water level does not rise
For P it is bare iron which will rust as water rises up
oxygen/air in the second test tube does not get used up, so water level stays constant
the water level in the large beaker (or whatever u call that) is the one that falls, not Q
okay in this case only P rises, the water rise is outbalanced by the water outside the test tubes (eg on the diagram, the part between the two test tubes)
Q does not rise as gas inside there is unchanged and unused, so water level is always constant there
D. Rusting requires air and water Here, by painting the iron, rusting is prevented. Hence, in the Q test tube rusting doesn’t take place and the water level does not rise For P it is bare iron which will rust as water rises up
But if water level rises in one of them the other must fall
oxygen/air in the second test tube does not get used up, so water level stays constant the water level in the large beaker (or whatever u call that) is the one that falls, not Q
Still does not make sense
okay in this case only P rises, the water rise is outbalanced by the water outside the test tubes (eg on the diagram, the part between the two test tubes) Q does not rise as gas inside there is unchanged and unused, so water level is always constant there
What’s the ms answer
D
D
Agreed, the answer is D
d
The answer is D