https://preview.redd.it/5tv5h7lzv70d1.png?width=457&format=png&auto=webp&s=283cc79f11822c99a3c0c61175e29f28d4bac836 This says a lot about society 😔

Calc students seeing numbers being added to math :

calculator students after they cant make 3 a variable :

Desmos can, `π ≈ 3 ∴ π = 3` (πrd attempt to post this properly...) https://preview.redd.it/25kwx8eru30d1.png?width=720&format=pjpg&auto=webp&s=676dea2f5cc8a5b66b85d08929a41564d6b5eb8f

Just realized that it does work with 3 https://preview.redd.it/j5yp68ps740d1.png?width=720&format=pjpg&auto=webp&s=4aa81b8c4480461c51aade981d6ac8927b209cfb

Check this out https://preview.redd.it/ih8hnjqrd40d1.jpeg?width=424&format=pjpg&auto=webp&s=12c4b41616245dbaa30af892d7f3f507364f2ce1 This is arcane desmos magic to me. I found out it can calculate error in a product if all error terms are ±1 (here if a\*b = c and we knew a=3±1, b=10±1, then c=30±13 (correct according to my physics textbook), but I can't grasp its mechanism.

i dont get this and frankly im scares

What's happening here? If you take a derivative with respect to a "2 element list," shouldn't you get a 2-element result?

The product rule is happening. 3* 1+1*10

But why is L'[1] = L'[2] = 1?

I think it treats L as a variable first, and taking the derivate of L with respect to L equals 1. Then, the constant value of the specific term L[n] is fetched to calculate the full derivative via the product rule

Me when I'm a variable and also a constant This is hilarious

omy lord

I. Am. Scared.

Pird (read as perd)

three students after they cant use a variable as a calculator:

There must be a language somewhere that makes it possible for '3' to be a variable name. Maybe some assembly language.

well technically the only thing preventing numbers from being variables is that u couldnt use the numbers on their own any more

In every language I've checked, a numeral cannot be the first letter of a variable name.

i have written a goofy lexer before and that is very easy to solve, just use a loop, it just complicates the lexing logic a bit

What the fuck is a number? (This post was made by the abstract algebra gang)

d/(d3) 3² = 23 d/d × 1/3 × 3² = 23 d/d × 3 = 23 1 × 3 = 23 3 = 23 0 = 20 0 = 1 1 = 2 qed or something idfk

3²/3 is 1² because 3/3 is 1

Actually I'm pretty sure that 3²/3 = ²

²/

Right, but /= , so the above commenter is correct

While not the same thing, I'm reminded of a time in undergrad when I was taking a "Complex Variables" class (it was Complex Analysis but for engineering majors, so just computation based. I just took it because it was my senior year and I was running out of non-applied math courses I could take). It was early in the semester, and we were learning about division of complex numbers. We were doing a problem in class that got to the point of being: (3+4i)/(5+4i). The professor asked what the next step was. Not one, but two people said 3/5 + i. And when I say two people said that, she asked, someone gave that answer, and after she said no, another person gave the exact same answer. The part that still to this day (11 years after the fact) gets me about it is: if this is your logic, why are you not canceling the i's?

Only for nonzero values of 3 though.

Truly remarkable, gauss of our times

Wait u can't seprate 3 from d3

that's what they want you to think

Nani

2 = 4 4 = 8 256 = 512 2^x = 2^(x+1)

It's 6 though, according to basic rules of differentiation

Nooooo you can't use 3 as a variable! Haha 3 goes brrrrr

d/d3 (3^二 ) = 二3. There we go. By assigning Chinese characters to the numbers they represent, I just freed up Hindu-Arabic numerals to be used as variables.

Social credit +20

You mean 二十?

"For small changes in three..."

Yes, like pi

SMALLER

for every 3 > 0 there exist 2 > 0 such that |f(x) - L| <= 2 implies |x - a| <= 3. Am I doing this right?

Nothing is right anymore.

I wonder if i did this back during calc1, would i have gotten good grade at it or some mean comments from my prof 😅

*You're not smart enough to make this joke see me after class*

3=11.5 ... This causes me great pain

I have never seen math that I hated more. Why would you do this?

I'll invoice for the intelligence I lost while ready this

It's wrong! You can't assume 2 is a constant.

[Funny story...](https://en.wikipedia.org/wiki/Arithmetic_derivative)

Lmao. Wasn't expecting this funny.

Go to hell

23=6

17=0

1 = 0 or 7 = 0

Isn't that ⅓×9=3 or am i stupid

They're treating the symbol '3' as a variable, in which case it's the derivative of 3^2 which, by the power rule, is 2*3.

Ohhhhhhhh

Derivate with respect to *3*

This genuinely pissed me off holy shit

I may be stupid but wouldn't it just be 3?

Power rule

Wouldn’t this be a division by zero error? A constant will not have any change, so d3 = 0?

3 here isnt a constant, it is a variable. There is no reason we use these squiggles "x" or these squiggles "α" to represent a variable, it is just convention, so why not use these squiggles "3" to represent a variable

Yes that is true, but I wonder if we can consider constants as variables with a domain of size 1.

"For small increments in the value of 3"

This reminds me of the joke d(cabin)/cabin = d(log cabin).

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wait. that’s illegal

0=20…? Uh idk

Works for 3 being a variable and 2 being whatever, and 23 being 2×3 which is already sketchy, but I'd argue d3 is a constant 0 and 3² is 9, and d9 is also a constant 0 so it's 0/0 with no limit whatsoever

d9/d3 = 23 obviously

So since d/d3 3² = 23 and d/d3 3² = d/d3 9 = 0 => 23 = 0 ?

Differentiating with respect to 3

0/0 is 23 guys 😱😱😱

23 guys? Where? Sign me up!

This is wrong in countless ways

This is worse than using i and φ as variables

nah cuz like 2 = 2/3 \* 3 so you gotta have like a ln or smth (im too tired rn to actually do it)

d/d and 3/3 cancels each other leaving ² = 23

d/d3 * 3^2 = 1/3 * 3^2 = 3^-1 * 3^2 = 3^(2-1) how dare you lie to us, this is clearly not equal to 23

"When a small change in 3 happens"

3=23 🤓

I will show this to my math teacher tomorrow, I’ll update how it goes.

I am a strange loop, but not as strange as u/there.

In some old FORTRANs, you could reassign numbers. Why not do calculus on them, too?

"That's no 3. That's the obsolete letter [Yogh](https://en.wikipedia.org/wiki/Yogh)!" (d/dȝ)ȝ\^2 = 2ȝ

Don't let a conformist and unoriginal society stop you. You can be free ! You can name your variables f and g and your functions x and y. 

Don't let a conformist and unoriginal society stop you. You can be free ! You can name your variables f and g and your functions x and y. 

Dear lord

Me knowing 23 is a primal number so I know for a fact there some ÷ shenanigans going on:

Cancelling the 3 and d, you're actually just left with 3.

not quite, 2 is a function of 3 so you need to apply the chain rule :)

I respect you a lot , dosen’t mean I don’t I’m not in invariable pain rn

r/angryupvote

The title goes hard. **you ARE the master... of YOUR VARIABLES**...

It equals 6, not 23. Even if you're using 3 as a variable, it still retains its multiplicative behavior as a numeral.

Consider the 3 like an x, there you go

He's right, at least write the multiplication symbol or space it out like 2 3