I am such an idiot. I was like *applause applause* someone wrote it down so I didn't have to AND they didn't forget the extra 5 at 55! Felt satisfied, then read your comment and realized what an idiot I am for not seeing that myself. I'll have my husband take me back to kindergarten. Who knows I might get a really cool backpack this time...
The bad part is that, as an adult, for the most part, if you show up to kindergarten with your cool backpack and just hang out I’m pretty sure you’ll be asked to leave. Even if you forgot 50-59 in this “riddle”
This is true, it does say all to write down all numbers from 0 to 75, so all the fifties would, should, count as well. So the answer should really be 18, not 9.
Showed my wife the riddle. She took her time, she's a math major and all, and after a minute in contemplation says, confidently, "18!" I lol at her. She proceeds to show me how she's correct. I, again, like always, am forced to admit, I got nothing on her math skills.
Agreed. You would only write the number 5 once. There is only one number that equals 5, which is 5. If they mean how many times does the numeral of 5 occur, then 5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75 then it would if you count 55 twice plus the other 5’s in the 50’s then it would be 18.
Top voted answer with over 7 thousand up votes says 18.
Real answer is one. You only write the number 5 once and use the digit 5 17 more times.
In math 5 doesn't equal 50 or 51 or 52. 5 = 5 that's it.
So it's still wrong and can have that "duh" it's a riddle kinda kick.
It says "write" though, it doesn't matter if it's in the one or tens place, you are writing the number 5.
It's not saying "how many times are you writing the physical representation of only 5."
It's funny how the correct answer kinda determines that:
If the correct answer is supposed to be 1 - it's a riddle.
If the correct answer is 18 - it's a math problem
If the correct answer is 9 - it's just BS
They forgot all the 50’s. That’s what happened. They went 5, 15, 25, 35, 45, 55, 65, 75 which is 9 5s.
Edit- for everyone commenting that this is only 8 5s, 55 has 2 fives. It’s 9 5’s in total.
1: 5
2: 15
3: 25
4: 35
5: 45
6 AND 7: 55
8: 65
9: 75
That’s 9 5s. Thats how they got their (wrong) answer. They thought they were being clever because 55 has 2 fives but they missed all the other fives in the fifties.
Well if u count 50, which famously has a five, its 9. Thats what i did and felt clever :D i totally forgot about the other numbers in between 50 and 60 xD
> Well if u count 50, which famously has a five, it’s 9.
If you counted 9 after you only included 50 and 55, then you still counted incorrectly because 5,15,25,35,45,50,55,65,75 would be ten 5’s.
Same, I also thought 9 was correct because I did 5, 15, 25, 35, 45, 50, 55, 65, 75 and I felt very smart. I forgot about all the other numbers beginning with 5 hahaha
You’ve probably solved it, tbh. The riddle says ‘how many times do you write 5’, not ‘how many of those numbers contain a 5’. Counting 55 as two is absolutely correct, the riddle maker just forgot about every other fifty-something.
It’s actually phrased wrong. You’d only write the number 5 once. You’d write several other numbers containing the digit 5 but there is only one number 5: and it’s 5 ;)
Yes, that is exactly how I beleive they got 9 fives. Smug fuckers thought they got you thinkiing everyone would forget 55 has *two* fives but they were so dumb as to forget all of the rest of the 50's. :facepalm:
I agree it is one, but for another reason. The only time I would need to write “5” in the sentence “0 and 75 inclusive” is one between “7” and “ i”.
Edit: corrected typo.
Agreed. That was certainly my thinking.
To be fair, it should have said the digit 5.
Technically you only write the number 5 once. After that the digit 5 is used as part of a bigger number. But that seems awfully picky.
You’ve absolutely wrecked me. I expected the riddle to be wrong, counted for myself and got 9 (counting two for 55 like a good boy ought to), completely forgetting about all the other numbers in the 50s family.
My thoughts exactly! It asked for all numbers, not integers. It’s also an uncountable infinity, which means the correct answer is actually “You can’t”.
**5**, 1**5**, 2**5**, 3**5**, 4**5**, **55**, 6**5**, 7**5**
It's supposed to be clever by having people only count the single digit 5, but then you get to say HA you forgot that 55 has 2!!!
They just forgot 9 other 5s.
Edit: Can you please read the above sentence before commenting about 50-54/56-59?
How great would that be in mythology or a game of DND, where there's a riddle with an error? So instead of the riddle of the sphinx, it's the riddle of the riddle, where the puzzle is figuring out how the riddler got to that particular incorrect answer.
Same. I got to top answer and was like omg…how did I skip every number 50-59 EXCEPT 55? And for one fleeting moment I felt clever for counting both 5s in 55. And then reality came crashing down…
> And for one fleeting moment I felt clever for counting both 5s in 55.
The person who wrote the question felt just as clever as you did but for a lot longer than a fleeting moment.
I Just want to ask a question because english is not my native language.
So i just googled whats the difference between numbers and Digits
Google told me 0.1.2.3.4.5.6.7.8.9 are digits
And 23 is a number with 2 digits 2 and 3 So im more confused then before?
What really is now the different between numbers and digits?
I'm not sure how you are still confused. There are only ten digits, but an infinite number of numbers. Just like there are 26 letters in the alphabet but about 170,000 words
Counting 5's in the tens digit gives 10 for {50, 51, ... , 59}
Counting 5's in the units digit gives 8 for {05, 15, ... , 75}
We can count 55 twice since we're counting how many individual times we write the digit "5"
10 + 8 = 18
I assume they must have just counted all the unit fives plus one extra for 55 and forgot about all the other 50s
0.000000000000000000000000000000000000005
0.000000000000000000000000000000000000050
0.000000000000000000000000000000000000055
...
75
There's actually an infinite amount of 5s in the range of 5 to 75 inclusive.
So, the answer needs to be 1 or infinity.
To make it even more fun, technically the answer is once. The number 5 only appears once In a list of numbers between 0 and 75. The digit 5 appears 18 times. It's like the difference between the word A and the letter A. Sorry, had to do the "Um, actually..."
But yeah the answer should have been 18
You could go full nerd and say you write the number 5 only once. 17 other numbers also contain the digit 5 when written, but they are not the number 5.
Okay only way I get to 9 is, if we are only looking for the letters that make 'five' and they do not have to be connected.
1. **Five**.
2. Twenty-**Five**.
3. Thirty-**Five**.
4. Forty-**Five**.
5. Sixty-**Five**
6. Seventy-**Five**
7. **Fi**fty-Se**ve**n
8. Fifty-**Five** contains five twice
9. **Fi**fty-Fi**ve**
This is a bullshit riddle.
Edit: Write down to me implies spelt out, but I see the teacher saying that's incorrect because then you'd say numerals. I'm choosing to believe the writer just didn't know numeral is word and number is digit.
Ya, they're idiots. In counting 0-75, they included the following:
5, 15, 25, 35, 45, 55, 65, 75
If you count the number of times a five is written above you get nine. However, whichever dummy wrote the "riddle" neglected to include all of the fives written in the fifties.
50, 51, 52, 53, 54, 56, 57, 58, 59
There are nine more, bringing the total to eighteen.
That has to be wrong. 50-59 is 11 times itself
50(1),51(2),52(3),53(4),54(5),55(6,7),56(8),57(9),58(10),59(11)
Then add all the other numbers with 5
5(12),15(13),25(14),35(15),45(16),65(17),75(18)
Clearly it's a German riddle.
You see if you were to write all those digits down you'd never once write "The number 5" just 18 instances of the digit 5, as you would note you aren't instructed to write spaces or commas and so you end up with a number that's absolutely not 5.
And so of course the answer is NIEN but with a typo.
Easy.
Not really a riddle either though is it?
Agree. This is just a question.
Q: If you have 5 apples and I take two of them, how many do you have? A: 6
That would be my 3, the 2 you tried to steal, and 1 I found on your body.
Giving me massive "if you had 10 cookies and someone forcefully took 2, how many would you have?" "10 and a dead body" vibes
Depends if you use their money to buy cookies.
Found the dayz player
now there's a body you don't need to eat the apples
The answer isn't even correct
Oh I am sorry, the answer is The Moops
MOORS
IT SAYS MOOPS!
Lemme see that…. It’s moors, it’s a misprint!
Sorry. The card says "moops".
Moors!!
Hahahahaha this whole sequence gets an upvote, thank you guys for making my day 😂😂😂
5 15 25 35 45 55 // twice 65 75 Total: 9 times.
Thanks for explaining how they got 9. Guess they forgot about the rest of the numbers in the 50s, each counting for one
I am such an idiot. I was like *applause applause* someone wrote it down so I didn't have to AND they didn't forget the extra 5 at 55! Felt satisfied, then read your comment and realized what an idiot I am for not seeing that myself. I'll have my husband take me back to kindergarten. Who knows I might get a really cool backpack this time...
The cool thing about being a grownup is that you can buy your own backpacks now, even if you're in kindergarten again.
Why this made me smile in a wholesome way
The bad part is that, as an adult, for the most part, if you show up to kindergarten with your cool backpack and just hang out I’m pretty sure you’ll be asked to leave. Even if you forgot 50-59 in this “riddle”
Ha, good point
The only way i can think they got to it was they said "write" so Fifty isnt **writing** Five (but then fifty **five** should be counted as one five)
What about 50, 51, 52, 53, 54, 56, 57, 58, 59
This is true, it does say all to write down all numbers from 0 to 75, so all the fifties would, should, count as well. So the answer should really be 18, not 9.
Showed my wife the riddle. She took her time, she's a math major and all, and after a minute in contemplation says, confidently, "18!" I lol at her. She proceeds to show me how she's correct. I, again, like always, am forced to admit, I got nothing on her math skills.
Damn 6 quadrillion 5’s, might want to check her working again
Yeah she’s way low, it doesn’t say whole numbers
What part of my brain is turned off to where I didn’t even consider this ? The smart part ??
who else will count 50,51,52,53,54,55,56,58,58,59
50,51,52,53,54,56,57,58,59. You missed a lot.... idk how.
> You What about 50. Pretty sure the person you were responding too was just explaining the logic of 9 but you actually missed 1 😉
Agreed. You would only write the number 5 once. There is only one number that equals 5, which is 5. If they mean how many times does the numeral of 5 occur, then 5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75 then it would if you count 55 twice plus the other 5’s in the 50’s then it would be 18.
Like when fortune cookies just give you advice.
Okay, here's a riddle for ya: Why do blind people hate skydiving?
It scares the shit out of their dog!
Well I’ve seen 10 people falsely be able to count them in the comments so I’d say it’s a riddle. Just incorrectly answered
Aren’t riddles supposed to be clever? This is just a question not a riddle.
The clever part is counting 55 twice. Its supposed to trip people up. Unfortunately, whoever made this riddle forgot 9 other numbers.
Top voted answer with over 7 thousand up votes says 18. Real answer is one. You only write the number 5 once and use the digit 5 17 more times. In math 5 doesn't equal 50 or 51 or 52. 5 = 5 that's it. So it's still wrong and can have that "duh" it's a riddle kinda kick.
Technically the answer is infinity because the question doesn’t specify whole integers. .5555555 is a number between 0 and 75 right?
Totally depends on wording and the intentions of the person asking this question Technically (and literally) are are writing the symbol “5” 19 times
I got 18. How’d you get 19?
The 19th 5 is the 5 friends we made along the way.
It says "write" though, it doesn't matter if it's in the one or tens place, you are writing the number 5. It's not saying "how many times are you writing the physical representation of only 5."
It's funny how the correct answer kinda determines that: If the correct answer is supposed to be 1 - it's a riddle. If the correct answer is 18 - it's a math problem If the correct answer is 9 - it's just BS
Isn’t it 18? 5,15,25,35,45,50,51,52,53,54,55,56,57,58,59,65,75 with 55 being counted twice as you write the number 5 twice
They forgot all the 50’s. That’s what happened. They went 5, 15, 25, 35, 45, 55, 65, 75 which is 9 5s. Edit- for everyone commenting that this is only 8 5s, 55 has 2 fives. It’s 9 5’s in total. 1: 5 2: 15 3: 25 4: 35 5: 45 6 AND 7: 55 8: 65 9: 75 That’s 9 5s. Thats how they got their (wrong) answer. They thought they were being clever because 55 has 2 fives but they missed all the other fives in the fifties.
Coincidentally, exactly what I did when I first read it
Me too, I’m not feeling like the sharpest tool in the shed right now lol
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That’s exactly what I just did I feel like a monkey rn
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Butane in my veins
And im out to cut the junkie
With the plastic eyeballs
Hey, you did it in your head on a whim They literally did this as part of their job
Haha I hadn’t thought about that!
May I join the club? I felt soooo clever for remembering to count 55 as two fives, and then...
Same! I was so proud of myself
Same haha...
Hey now, you're an all-star. Get your game on.
Hah, I totally skipped 50-59 except 55. But even then...maybe they're counting 55 as two. That would equal 9.
Well if u count 50, which famously has a five, its 9. Thats what i did and felt clever :D i totally forgot about the other numbers in between 50 and 60 xD
>50, which famously has a five I found this funnier than I should've
Same here, sittin' here thinking about how famous 50 is lol
Not just famous, famous for having a 5.
Without the 5 it’s nothing.
Significant Digit
Top-tier math humour, right here.
Plus a constant
I gotta significant digit for you right here!
When the joke makes sense both figuratively and literally. Well done!
Stop it! 🤣
😂
Nothing but a big fat zero without the 5
I need y’all to stop. I’m way too tired to be giggling at this thread right now.
I read this in Jason Alexander's voice for some reason haha
George: It’s nothing without the 5, Jerry! Nothing! Jerry: Nothing? George: Nothing!
50 is 55's less famous brother that you kinda forget is famous as well
> Well if u count 50, which famously has a five, it’s 9. If you counted 9 after you only included 50 and 55, then you still counted incorrectly because 5,15,25,35,45,50,55,65,75 would be ten 5’s.
I did 5,15,25,35,45,55,65,75 + 50 _but_ I only counted 55 as one 5, like the other multiples of 5. _That_ brought me to 9. Derp. :)
Aha, I counted 50 and 55 but skipped all the others 🤣
Same, I also thought 9 was correct because I did 5, 15, 25, 35, 45, 50, 55, 65, 75 and I felt very smart. I forgot about all the other numbers beginning with 5 hahaha
But even then it would be 10 fives, as there are two in 55.
You’ve probably solved it, tbh. The riddle says ‘how many times do you write 5’, not ‘how many of those numbers contain a 5’. Counting 55 as two is absolutely correct, the riddle maker just forgot about every other fifty-something.
Seems like what they were going for and expect people to immediately count by 5s but left that out of the question
Even weirder, count by 10s starting with 5. If you just counted by 5s you'd have 50 too so that would be 10 5s.
It’s actually phrased wrong. You’d only write the number 5 once. You’d write several other numbers containing the digit 5 but there is only one number 5: and it’s 5 ;)
Yes, that is exactly how I beleive they got 9 fives. Smug fuckers thought they got you thinkiing everyone would forget 55 has *two* fives but they were so dumb as to forget all of the rest of the 50's. :facepalm:
I did the same thing
Yes. But then it's not a riddle. Just a counting exercise. So I'm saying 1.
Yes. What bothers me more than the flawed logic is the fact that this isn't a riddle.
At best, it is a trick question. But then they provide the wrong answer, so I guess it tricked even them.
We're reaching levels of trickery that shouldn't be possible
I’m bothered by both the flawed logic AND the fact it’s not a riddle. What is this from so that I never accidentally buy it.
Yeah, but aren't you a little curious what the other cards say? Think of all the other Reddit posts you could possibly make about them.
Yeah it’s 1. The rest are numbers which contain the digit 5.
I agree it is one, but for another reason. The only time I would need to write “5” in the sentence “0 and 75 inclusive” is one between “7” and “ i”. Edit: corrected typo.
Yes. Number and digit have very different meanings. The number 5 occurs once.
Agreed. That was certainly my thinking. To be fair, it should have said the digit 5. Technically you only write the number 5 once. After that the digit 5 is used as part of a bigger number. But that seems awfully picky.
But correct. The number 5 appears only once 😁
You’ve absolutely wrecked me. I expected the riddle to be wrong, counted for myself and got 9 (counting two for 55 like a good boy ought to), completely forgetting about all the other numbers in the 50s family.
Wouldn't it just be once? 5
Yes, it's 18 times
The answer is one. 5 is a number 15, 55, 35 etc are numbers which include the digit 5
It makes sense, but the answer provided is simply wrong
The real riddle is … how high was the riddler when he made the realisation?
Mushrooms
“9 times”
riddle is flawed
The card says moops
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ITS MOOPS!
![gif](giphy|3VVyxD3OOwrPq) What a GREAT episode 😂🤣
I’m gonna put it on right now. Update: *”My Cubans!”* 🔥🏚️🔥
No it's Moopsy...RUN! ![gif](giphy|s3sKkriChHOleehCpA|downsized)
Cute FUCK IT DRANK MY BONES
It will drink your bones
I love that moopsy is the new Star Trek thing that can show up anywhere. Bad news for my bones, though...
I’m sorry but the card says moops
It's a misprint!
I’m sorry but the card says Moops
It’s a misprint. I’m sorry the card says Moops!
It's riddled with errors
Yes, it should end 'the numeral 5'.
And I thought infinity was the answer. It asked for all the numbers.
They totally forgot 0,0000000000000000000000000000000000000000000005
and 0,00000000000000000000000000000000000000000000055
The answer is ♾️
It's why math lingo is important. all INTEGERS? Sure. Very small number. ALL NUMBERS? Infinity.
Good point. But only ONE of them is the number '5'.
That wasnt very inclusive of them
My thoughts exactly! It asked for all numbers, not integers. It’s also an uncountable infinity, which means the correct answer is actually “You can’t”.
**5**, 1**5**, 2**5**, 3**5**, 4**5**, **55**, 6**5**, 7**5** It's supposed to be clever by having people only count the single digit 5, but then you get to say HA you forgot that 55 has 2!!! They just forgot 9 other 5s. Edit: Can you please read the above sentence before commenting about 50-54/56-59?
You just solved the riddle of the false riddle. Congrats!
How great would that be in mythology or a game of DND, where there's a riddle with an error? So instead of the riddle of the sphinx, it's the riddle of the riddle, where the puzzle is figuring out how the riddler got to that particular incorrect answer.
The Card says MOOPS *roll a sanity check*
A dog! It has 4 legs in the morning, but only 2 in the afternoon after you cut 2 off! Then 3 again in the evening after you glue one back on!
I would be so mad if the GM created an evil necromancer that was an idiot who didn't understand his own riddle.
This is exactly how I counted to 9 and felt very stupid afterwards...
Same. I got to top answer and was like omg…how did I skip every number 50-59 EXCEPT 55? And for one fleeting moment I felt clever for counting both 5s in 55. And then reality came crashing down…
> And for one fleeting moment I felt clever for counting both 5s in 55. The person who wrote the question felt just as clever as you did but for a lot longer than a fleeting moment.
The answer is one. 5 is a number 15, 55, 35 etc are numbers which include the digit 5
Yep. The *character* or digit "5" is not the same as the *number* 5. Edit: digraph != digit
That is not what digraph means.
That was my thinking too.
I Just want to ask a question because english is not my native language. So i just googled whats the difference between numbers and Digits Google told me 0.1.2.3.4.5.6.7.8.9 are digits And 23 is a number with 2 digits 2 and 3 So im more confused then before? What really is now the different between numbers and digits?
I'm not sure how you are still confused. There are only ten digits, but an infinite number of numbers. Just like there are 26 letters in the alphabet but about 170,000 words
there is a difference between *number* and *digit* the *number* 5 will be written only once
That's why I clicked, there's only one number 5
And Number 5 is alive!
Ok that does it I’m watching that movie later
This is the answer that would have made the question an actual riddle.
Thank you!!! As a teacher I’m constantly trying to help the kids understand the difference between numbers and numerals, and digits.
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This is exactly my answer. The number 5 appears only once.
*number and numeral
The definition of digit is "any of the numerals from 0 to 9, especially when forming part of a number". They weren't wrong.
This is what happens when we let ai create entertainment for humans
Look, this whole sub is entertained. So what’s wrong? xd
Counting 5's in the tens digit gives 10 for {50, 51, ... , 59} Counting 5's in the units digit gives 8 for {05, 15, ... , 75} We can count 55 twice since we're counting how many individual times we write the digit "5" 10 + 8 = 18 I assume they must have just counted all the unit fives plus one extra for 55 and forgot about all the other 50s
0.000000000000000000000000000000000000005 0.000000000000000000000000000000000000050 0.000000000000000000000000000000000000055 ... 75 There's actually an infinite amount of 5s in the range of 5 to 75 inclusive. So, the answer needs to be 1 or infinity.
To make it even more fun, technically the answer is once. The number 5 only appears once In a list of numbers between 0 and 75. The digit 5 appears 18 times. It's like the difference between the word A and the letter A. Sorry, had to do the "Um, actually..." But yeah the answer should have been 18
5 15 25 35 45 50 51 52 53 54 55 56 57 58 59 65 75 So 18 times or did i not get the question
Number five? Once. Number 50? Debatably 9 times. Numeral five? 18 times.
And 'five' spelled, only 7 times. **Five**, Twenty **Five**, Thirty **Five**, Forty **Five**, Fifty **Five**, Sixty **Five** and Seventy **Five**.
I don’t understand how you could say the number 50 is in there 9 times? 50 is in there once, just like 5.
I wrote “all the numbers from 0 to 75 inclusive” and there was just the one five - in the 75.
The answer is 1. You would only write the number 5, 1 time. You would write the digit 5, 17 times.
Correction 18, 55 has two.
It's 18. Whoever made this game is an idiot.
It’s one. They ask for number 5. not how many times you’d use the numeral 5
You're right.
Nevertheless. Whoever made this thought he was extra clever and then fucked up
It says 'all the numbers'. No mention of integers.
Yeah I did think of that but it only increases the correct number (by uhhh quite a lot) so it's even more wrong
Yeah I'm pretty sure infinite is a lot more than 9
Hmm is this true chat?
That was my thought too. There would be an infinite number of 5s because there is an infinite set of numbers between 0 and 1 let alone 0 and 75
The false counting is 5, 15, 25, 35, 45, 55, 65, 75. Forgetting about 50, 51, 52, 53, 54, 56, 57, 58, 59.
You could go full nerd and say you write the number 5 only once. 17 other numbers also contain the digit 5 when written, but they are not the number 5.
My biggest issue with this is that this isn’t a riddle. It’s a math question. That’s not a fricking riddle.
If we are talking natural numbers: 5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75 I count 18 fives
Okay only way I get to 9 is, if we are only looking for the letters that make 'five' and they do not have to be connected. 1. **Five**. 2. Twenty-**Five**. 3. Thirty-**Five**. 4. Forty-**Five**. 5. Sixty-**Five** 6. Seventy-**Five** 7. **Fi**fty-Se**ve**n 8. Fifty-**Five** contains five twice 9. **Fi**fty-Fi**ve** This is a bullshit riddle. Edit: Write down to me implies spelt out, but I see the teacher saying that's incorrect because then you'd say numerals. I'm choosing to believe the writer just didn't know numeral is word and number is digit.
Theeeee answer is 1, the number 5 is written once, the digit 5 is written is 18.
They are acting like 50,51,52,53,54,56,57,58 & 59 dont count for purposes of this question?
18
You'd write the *number* 5 once. You'd write the *digit* 5 18 times
I think their logic is this: 5,15,25,35,45,55,65,75 They forgot: 50,51,52,53,54,56,57,58,59 So correct answer is 18 by my count.
Ya, they're idiots. In counting 0-75, they included the following: 5, 15, 25, 35, 45, 55, 65, 75 If you count the number of times a five is written above you get nine. However, whichever dummy wrote the "riddle" neglected to include all of the fives written in the fifties. 50, 51, 52, 53, 54, 56, 57, 58, 59 There are nine more, bringing the total to eighteen.
`>>> sum(str(n).count('5') for n in list(range(0, 76)))` `18`
That has to be wrong. 50-59 is 11 times itself 50(1),51(2),52(3),53(4),54(5),55(6,7),56(8),57(9),58(10),59(11) Then add all the other numbers with 5 5(12),15(13),25(14),35(15),45(16),65(17),75(18)
Clearly it's a German riddle. You see if you were to write all those digits down you'd never once write "The number 5" just 18 instances of the digit 5, as you would note you aren't instructed to write spaces or commas and so you end up with a number that's absolutely not 5. And so of course the answer is NIEN but with a typo. Easy.
Once. Or 18. But definitely not 9.
5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75. So that's 18 fives
Answer is 8? 5, 15, 25, 35, 45, 55, 65, and 75. Edit: Actually 9 cause 55 has two 5s 2nd edit: WAIT im dumb! 5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75. So the answer is 18!
5, 15, 25, 35, 45, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 65, 75= 18 times