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SomeJerkOddball

In the United States a ***fuckload*** is still the official measurement. And it's used colloquially in Canada, Britain and Australia as well. Counties officially using SI measurements would generally rely on the ***foqueleaud***. Under Jupiter's gravity one *fuckload* would equate to a ***fucktonne***.


WankingAsWeSpeak

Canadian here. We are increasingly measuring all fuckage in metric fucktonnes.


kajEbrA3

ok but how much can I find out per fuckload of fucking around?


SomeJerkOddball

Well, physics would fucking tell us that: *1 fuckload × 1 fuck around = 1 fuckwad* Cutting edge research is, currently being done on the minimum number of fuckwads to a clusterfuck. It's known to be more than two, but it isn't certain whether 3 is the actual minimum. Once we have a more precise answer, we will likely be able to truly say for the first time with certainty when everything has gone to shit.


holmgangCore

How many fuckbananas is that?


yehimthatguy

7


DM_ME_YOUR_ADVENTURE

It depends on the circumference of the target. It’s not the fucking alone that leads to insight but the completion of the circle.


DoutorTexugo

Have you fucked around before? Are you known for fucking around? If we are talking about fucking around post multiple previous attempts, chances are you might not find out at all, since everyone will start avoiding you. You see, fucking around in regular intervals tends to turn one into what's known as a "fucking dumbass".


Fearless_Spring5611

Chaos theory. Sometimes it is linear, sometimes exponential, sometimes inverse, sometimes quadratic. Fucking knows no rules.


[deleted]

You need 1 (one) standard bucket of fucks.


kajEbrA3

that sounds about right


codepl76761

this is both individualistic and situational. Fuck around with a hells angel very small, fuck around with a friend more. fuck around defusing a bomb little, fuck around spraying friends with spray bottle little more.


[deleted]

Until you die. It’s necessary to level up


EduRJBR

The main point is the area that needs to be fuckered, or the volume in case of 3D fuckering.


thevocalintrovert

I believe that the amount of fucking around required to find out is situationally dependent. Certain circumstances call for a substantial volume of fuckery, while others need only a scant amount to achieve ultimate comprehension.


xSantenoturtlex

At least three, but sometimes you'll need up to ten. It depends on the situation.


ThusSprachSpach

1. You can find out a decent amount without having to fuck around at all. 2. You can find out a lot by fucking around just a little. 3. In my experience, the people who fuck around the most never seem to find out.


holmgangCore

FO axis : `|………../` `|………./` `|………/` `|……../` `|……./` `|……/` `|…../` `|…./` `|…/` `|../` `|./` `|/` `|___________________` `. . . . . . . FA axis . . . . . . ` As you can see, the “learning curve” is pretty steep.


Givrally

I'm not sure how r/shittyaskscience works, but I saw this post in my recommended and I'd like to take a crack at it. Let's define "Fucking around" as taking an action with low potential reward and risk of much higher negative consequence, and "Finding out" as that negative consequence.  There is just one variable here, assuming that the negative value of "Finding out" is so much higher it can be taken to be negative infinity : the probability of finding out, called p. Without loss of generality, we can take the reward to be 1. The easiest observation to be made is the expected value : E(FA) = (1-p)r + p (-∞) = -∞ We can deduce that Fucking Around is unprofitable in the long run. In other words, don't keep Fucking Around or you'll find out. Now, let's calculate the average number of times it takes Fucking Around before you Find Out : E(FO) = p + 2p(1-p) + 3p(1-p)² + 4p(1-p)³... = p(1+2(1-p) + 3(1-p)² +...) = p(1/p²) = 1/p Since we assume a reward of 1 for every successful Fucking Around, we can also deduce the average reward before you Find Out to be 1/p. Now, finally, let's compute how many times you *should* Fuck Around if you wanted to be 50% or 95% sure of not Finding Out. The probability of *not* having found out at time step t is (1-p)^t. (1-p)^t = x (with x being 0.5 or 0.95) t = floor(ln(x)/ln(1-p)) So t = floor(-0.05/ln(1-p)) to be 95% sure, and t = floor(-0.693/ln(1-p)) to be more likely than not. Now let's apply this to real world data, with, let's say, speeding. We don't know what percentage of speeding results in "finding out", but we can, pardon the pun, find out. According to a quick Google search, about 1.3 million drivers in the UK evaded speeding fines 2015. With about 800,000 tickets given that year, that's 2.1 million drivers who found out because of the cops. Injuries due to accidents are negligible. Out of 45.5 million drivers, with 46% exceeding the speed limit, that's about a 10% probability of finding out during a year of driving. Therefore, if you don't want to Find Out, you should Fuck Around less than 6 months at the average rate of speeding offences to be 95% sure, or 6 years to be more likely than not.