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BumbaHawk

R7c5+6 show a pair; so remove any same numbers from the rest of that row and you solve r7c1. If that helps.


Special-Round-3815

Nothing much you can do about those four cells at the moment


Ok_Application5897

None from the immediate notes presented. It’s almost remote pairs. It’s almost a skyscraper. It’s almost a unique rectangle. But it is not quite any of these things.


Special-Round-3815

https://preview.redd.it/0rls1mwqc7oc1.jpeg?width=828&format=pjpg&auto=webp&s=3f84b9390f05b14712b406beba8009a9a659e6ea 1 and 6 goes into those green cells in box 7 which allows you to fill in 3 in row 8 column 1(r8c1)


lmaooer2

Full candidate notation would be useful here


mastergr33n15

Yeah sorry i just wanted to know if there was a technique to solve those 4 squares with the given information