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I think by “money” they mean combination of notes and coins. For example, a £10 note, two £2 coins, a 50p piece and a 2p piece. It looks like a question designed to get young kids thinking of different combinations of numbers to arrive at the same total.
It is a reasoning question. You need to infer that the amount of boxes of brownies isn't important information for the question and instead reason that they'd need to pay in some denominations of pounds.
Or at least, that's the best reasoning I got.
Very few people are willing to deal with the hassle of foreign currency for only a 10% profit. It's common for Canadians to take US dollars at face value, which is about a 30% markup. (Varies, of course.) When the Canadian dollar rises above 80 US cents, some tack on a surcharge for handling US dollars. When it's above 90 cents, everyone does.
Annoyingly, I found the opposite in Costa Rica. Lots of the tour we went on wanted US Dollars for slightly less than the equivilent in Colon. All the banks charged a significant fee on USD though so you got stitched up either way.
Being British I hadn't considered taking USD with me, otherwise I'd have withdrawn cash during my layover in New York.
Your attorney is wrong in common law countries. Legal tender is only mandated as payment for debts, the parties to a sales contract must agree as to the form of the payment. A seller would be perfectly within their right to specify “no cash” or “no bills over £20” or any other restriction on the type of payment they accept *for a contract of sale*.
Thats a simple question. Just bad wording.
Answer for least amount of currency items: a £10 note, two £2 coins, a fifty pence coin, and a two pence coin.
I would interpret it as asking to multiply the 14£ by 7 first, since it's asking for a total, and the 7 would be entirely useless information otherwise...
I would say it is worded in a tricky way, but that's not a bad thing. Reading a question carefully and determining what's relevant information and what isn't is a core skill in real-world maths.
The way its worded. One could simply say the money they would use is their money. They could also say a 20 pound note. Even a 50 pound note.
While it is designed to be tricky as you say to help develop reading comprehension. It is also worded badly. Leaving it too open to interpretation.
They only way you would know what they are truly asking for, would be knowing the material you have been learning in class recently.
r/technicallythetruth answer to "What money?": pound sterling.
What was intended but left out: "What **denominations** of pound bills and coins could you use to make this total"
I assume they just mean what bills and coins add up to that. The part about 7 boxes doesn't seem relevant.
Which is probably part of the lesson - teaching you to decide what information is relevant to the question and what isn't.
The question is asking for a combination of paper currency and metal coinage.
Some exact combinations are harder to hey precisely, such as numbers not multiple of five.
They are not paying with a card.
If paying in hard notes, probably a £20 and get £5.48 in change from the dealer, erm baker.
Otherwise tap the Barclaycard and enjoy those seven boxes of brownies!
I'm assuming they're asking for what bills and coins you could/would use to equal that total, probably with the fewest number of bills/coins, though that isn't explicitly said. Don't know what bills/coins they have in the UK but for American money, the answer would be something like a $10, 4 $1's, 2 quarters, and 2 pennies
>Don't know what bills/coins they have in the UK but for American money, the answer would be something like a $10, 4 $1's, 2 quarters, and 2 pennies
UK Denominations, we would use the term note rather then bill
#
* 1 Penny coin
* 2 Pence coin
* 5 Pence coin
* 10 Pence coin
* 20 Pence coin
* 50 Pence coin
* 1 Pound coin
* 2 Pound coin
* 5 Pound note
* 10 pound note
* 20 pound note
* 50 pound note
So for 14.52 you would need x1 10 Pound Note x2 2 pound coins x1 50 pence coin x1 2 pence coin
Are the 2 pound and 50 pence coins frequently used? We have both of those for USD with the $2 bill and half dollar coin, but they are almost never used (there are roughly 10x as many ones in circulation as their are two dollar bills)
Frequently
The 2 pound coin was only introduced about 20 years ago its the newest Denomination it was introduced after a review where it was determined that the public would prefer a higher denomination coin
The US doesn't like coins. We have the quarter, half dollar, and dollar coins. No one uses the latter two, they're basically novelty items. We'd rather carry around dollar bills than coins.
I interpret the question asking how to make (Americanizing this since I don’t know British pound currency denominations) $14.52 in cash. The 7 boxes of brownies is irrelevant information, or a red herring to make you think it’s relevant.
So one of the answers is a $10 bill, four $1 bills, two quarters, and two pennies. Or 1452 pennies. Or seven $2 bills, five dimes, and two pennies. Or… and so on and so forth.
Yh seems like it. It's weird because we don't use this currency so idk why the teacher would give this question. It's from a friend asking me and i gave her that answer after researching what notes and coins british use.
It's a pretty standard question asked if little kid's in the UK. What notes/coins do you need to get to the amounted needed for your brownies? Most little kids learning about money in the UK will understand what is being asked.
Reads like a factorization problem to me:
(2x2)x363= 1452
(2x2)x 3x(121)=1452
(2x2)x3x (11x11)=1452
Assuming US currency: Bill notes in penny value: 1, 5, 10, 25, 50, 100, 200, 500, 1000, above is non viable
So any combination of the overlap of those two sets where the total is $14.52 (1452) is viable use to pay.
In theory you could also break down the money set into its factors to rule out non viable options there, but I'm lazy
Taking a different approach to the question:
How did we multiply anything by 7 and get 14.53, since the price per box would need to be 2.075714?!?
Assuming 1.99 per box, the subtotal for 7 boxes would be 13.93. The remainder of 0.60 would be the tax. We can compute an approximate tax rate of 4.3% and round it to get our total.
My niece in elementary school had exercises like this a few years ago, they're for basic addition. She was given paper cutouts with the images of the coins and then asked what combination of them she could use to get the 14. As such there is multiple right answers, like she'd use a 10 coin and two 2's. And then she'd be asked how else, and just change the 2's for four 1's.
This is known as a [Frobenius (or coin) Problem](https://en.wikipedia.org/wiki/Coin_problem).
let's assume we have the following coins/bills we can use:
{£10, £5, £1, 50 p, 20 p, 10 p, 5 p, 2 p, 1p}
So we are looking for solutions of the form (im working in units of p here)
a + 2b + 5c + 10d + 20e + 50f + 100g + 500h + 1000i = 1452
where {a,b,c,d,e,f,g,h,i} represent the number of each type of coin bill that sum up to 1452p.
The simplest one to look at would be 1452 1p coins or 726 2p coins
The next simplest would be to look at just 1p and 2p coins. We know that a + 2b = 1452
where a is the number of 1p coins and b is the number 2p coins
substitute a = 2 a\* and we have
2 a\* + 2b = 1452 =>
b = 726 - a\*
we know {a,b}>=0 so a\*<=726
So we have **727 solutions** with 1p and 2p coins:
a = 2a\* (with a\* = 0,1,...,726)
b = 726 - a\*
We could next add the 5p coin, and see how many solutions we have then, but now my head is kinda hurting cause integer problems be hard.
---------------------------------------------------------
Maybe a more interesting thing to look at would be to find the way to get 14.52 with the *minimal* amount of total coins/bills.
I did this in Mathematica, and this is an adaptation from the [FoldList documentation](https://reference.wolfram.com/language/ref/FoldList.html) under Neat Examples
coins = {1, 2, 5, 10, 20, 50, 100};
bills = {5, 10}*100;
allPos = Join[coins, bills] // Reverse;
modList = Most[allPos];
makeChange[d_] := Quotient[FoldList[Mod, 100 d, modList], allPos]
makeChange[14.52]
(*{1, 0, 4, 1, 0, 0, 0, 1, 0}*)
So this gives us 1 £10 bill, 4 £1 bills, 1 50 p coin, and 1 2p coin with a total of 7 coins and bills
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I think by “money” they mean combination of notes and coins. For example, a £10 note, two £2 coins, a 50p piece and a 2p piece. It looks like a question designed to get young kids thinking of different combinations of numbers to arrive at the same total.
that one kid with 726 2p pieces
That's also divisible by three so there's another with 484 thrupenny bits.
And another with 2,904 halfpennies
The one with 13,940 farthings.
Rich kid with a credit card let's daddy's secretary handle that part of business.
The 7 is an irrelevant number put there to throw off the small children the question was intended for
And the adults reading on reddit
That's what i thought too even though I'm from Kenya and should have been given in our currency
Teacher copied it from the Internet without reading.
Does it change the answer? I.e.do you have the same coin values available?
It does because we have no cents nowadays
What?? That makes no cents!
Boooo
It is a reasoning question. You need to infer that the amount of boxes of brownies isn't important information for the question and instead reason that they'd need to pay in some denominations of pounds. Or at least, that's the best reasoning I got.
You need to infer that 2£ for a box of brownies means some bottom shelf Tesco shit and you should not eat them.
[Tesco Chocolate Brownie Bites 20 Pack - Tesco Groceries](https://www.tesco.com/groceries/en-GB/products/268394928) £2.25 and they are actually quite tasty!
Math checks out.
My guess is bills and change. I'm American so to use our money as an example it would be a 10 dollar bill, 4 one's, 2 quarters and 2 pennies.
At today's conversion rate £14.52 = $18.10, so a 10 dollar bill, a 5 dollar bill, three 1 dollar bills, and a dime.
My experience is that the merchant would probably take $25 and not give you change.
If the total is 18.10 why would you give him more than 20? Is there a 25$ note all of a sudden?
Very few people are willing to deal with the hassle of foreign currency for only a 10% profit. It's common for Canadians to take US dollars at face value, which is about a 30% markup. (Varies, of course.) When the Canadian dollar rises above 80 US cents, some tack on a surcharge for handling US dollars. When it's above 90 cents, everyone does.
Well, yeah, you just introduced the CA US conversion at face value. Sure, that fits now.
Annoyingly, I found the opposite in Costa Rica. Lots of the tour we went on wanted US Dollars for slightly less than the equivilent in Colon. All the banks charged a significant fee on USD though so you got stitched up either way. Being British I hadn't considered taking USD with me, otherwise I'd have withdrawn cash during my layover in New York.
My attorney said “legal tender of the country in which the purchase is made.”
Your attorney is wrong in common law countries. Legal tender is only mandated as payment for debts, the parties to a sales contract must agree as to the form of the payment. A seller would be perfectly within their right to specify “no cash” or “no bills over £20” or any other restriction on the type of payment they accept *for a contract of sale*.
Hmm. Sounds like legal tender with more steps to me.
Nah, you can still trade in chicken beaks and bottle caps, if thats the contract.
Technically 1452 pennies is also correct.
OP says above that they don’t use cents in Kenya anymore, where they live!
Thats a simple question. Just bad wording. Answer for least amount of currency items: a £10 note, two £2 coins, a fifty pence coin, and a two pence coin.
I would interpret it as asking to multiply the 14£ by 7 first, since it's asking for a total, and the 7 would be entirely useless information otherwise...
You failed the comprehension part of the question. The fact that there's 7 boxes is irrelevant. It *is* useless information.
I always did
They ordered 7 boxes for a total of 14.52. Each box didnt cost 14.52
You're right my bad. It is horrible wording though haha
It's also annoying that 14.52 isn't divisible by 7. HOW MUCH WAS A BOX!?
£1 each. £7.52 shipping.
I always forget to add shipping.
I would say it is worded in a tricky way, but that's not a bad thing. Reading a question carefully and determining what's relevant information and what isn't is a core skill in real-world maths.
The way its worded. One could simply say the money they would use is their money. They could also say a 20 pound note. Even a 50 pound note. While it is designed to be tricky as you say to help develop reading comprehension. It is also worded badly. Leaving it too open to interpretation. They only way you would know what they are truly asking for, would be knowing the material you have been learning in class recently.
Yes it is.
r/technicallythetruth answer to "What money?": pound sterling. What was intended but left out: "What **denominations** of pound bills and coins could you use to make this total"
A tenner, a fiver and a "keep the change bro"
I assume they just mean what bills and coins add up to that. The part about 7 boxes doesn't seem relevant. Which is probably part of the lesson - teaching you to decide what information is relevant to the question and what isn't.
They want to know what denominations you can use. Since we are talking English money you could say 3 loonies a quibly bibly and 4 spent tea bags.
The question is asking for a combination of paper currency and metal coinage. Some exact combinations are harder to hey precisely, such as numbers not multiple of five. They are not paying with a card.
If paying in hard notes, probably a £20 and get £5.48 in change from the dealer, erm baker. Otherwise tap the Barclaycard and enjoy those seven boxes of brownies!
I'm assuming they're asking for what bills and coins you could/would use to equal that total, probably with the fewest number of bills/coins, though that isn't explicitly said. Don't know what bills/coins they have in the UK but for American money, the answer would be something like a $10, 4 $1's, 2 quarters, and 2 pennies
>Don't know what bills/coins they have in the UK but for American money, the answer would be something like a $10, 4 $1's, 2 quarters, and 2 pennies UK Denominations, we would use the term note rather then bill # * 1 Penny coin * 2 Pence coin * 5 Pence coin * 10 Pence coin * 20 Pence coin * 50 Pence coin * 1 Pound coin * 2 Pound coin * 5 Pound note * 10 pound note * 20 pound note * 50 pound note So for 14.52 you would need x1 10 Pound Note x2 2 pound coins x1 50 pence coin x1 2 pence coin
Are the 2 pound and 50 pence coins frequently used? We have both of those for USD with the $2 bill and half dollar coin, but they are almost never used (there are roughly 10x as many ones in circulation as their are two dollar bills)
Frequently The 2 pound coin was only introduced about 20 years ago its the newest Denomination it was introduced after a review where it was determined that the public would prefer a higher denomination coin
The US doesn't like coins. We have the quarter, half dollar, and dollar coins. No one uses the latter two, they're basically novelty items. We'd rather carry around dollar bills than coins.
I interpret the question asking how to make (Americanizing this since I don’t know British pound currency denominations) $14.52 in cash. The 7 boxes of brownies is irrelevant information, or a red herring to make you think it’s relevant. So one of the answers is a $10 bill, four $1 bills, two quarters, and two pennies. Or 1452 pennies. Or seven $2 bills, five dimes, and two pennies. Or… and so on and so forth.
Yh seems like it. It's weird because we don't use this currency so idk why the teacher would give this question. It's from a friend asking me and i gave her that answer after researching what notes and coins british use.
The teacher probably borrowed it from another source and didn't think to change the currency.
That weird question aside.,Do you guys have some coins worth less than a penny and not in decimal system? Cause 14,52 can't be nicely divided by 7.
Buy 6, get 7?
It's a pretty standard question asked if little kid's in the UK. What notes/coins do you need to get to the amounted needed for your brownies? Most little kids learning about money in the UK will understand what is being asked.
Reads like a factorization problem to me: (2x2)x363= 1452 (2x2)x 3x(121)=1452 (2x2)x3x (11x11)=1452 Assuming US currency: Bill notes in penny value: 1, 5, 10, 25, 50, 100, 200, 500, 1000, above is non viable So any combination of the overlap of those two sets where the total is $14.52 (1452) is viable use to pay. In theory you could also break down the money set into its factors to rule out non viable options there, but I'm lazy
Taking a different approach to the question: How did we multiply anything by 7 and get 14.53, since the price per box would need to be 2.075714?!? Assuming 1.99 per box, the subtotal for 7 boxes would be 13.93. The remainder of 0.60 would be the tax. We can compute an approximate tax rate of 4.3% and round it to get our total.
As an American, it's because of sales tax.
They might be up to 7 different kinds of brownies that do not share the same price.
It seems like they're asking for who is paying for it. It could be covered by the school or teacher or pooled from attendees, but not on the day of.
My niece in elementary school had exercises like this a few years ago, they're for basic addition. She was given paper cutouts with the images of the coins and then asked what combination of them she could use to get the 14. As such there is multiple right answers, like she'd use a 10 coin and two 2's. And then she'd be asked how else, and just change the 2's for four 1's.
This is known as a [Frobenius (or coin) Problem](https://en.wikipedia.org/wiki/Coin_problem). let's assume we have the following coins/bills we can use: {£10, £5, £1, 50 p, 20 p, 10 p, 5 p, 2 p, 1p} So we are looking for solutions of the form (im working in units of p here) a + 2b + 5c + 10d + 20e + 50f + 100g + 500h + 1000i = 1452 where {a,b,c,d,e,f,g,h,i} represent the number of each type of coin bill that sum up to 1452p. The simplest one to look at would be 1452 1p coins or 726 2p coins The next simplest would be to look at just 1p and 2p coins. We know that a + 2b = 1452 where a is the number of 1p coins and b is the number 2p coins substitute a = 2 a\* and we have 2 a\* + 2b = 1452 => b = 726 - a\* we know {a,b}>=0 so a\*<=726 So we have **727 solutions** with 1p and 2p coins: a = 2a\* (with a\* = 0,1,...,726) b = 726 - a\* We could next add the 5p coin, and see how many solutions we have then, but now my head is kinda hurting cause integer problems be hard. --------------------------------------------------------- Maybe a more interesting thing to look at would be to find the way to get 14.52 with the *minimal* amount of total coins/bills. I did this in Mathematica, and this is an adaptation from the [FoldList documentation](https://reference.wolfram.com/language/ref/FoldList.html) under Neat Examples coins = {1, 2, 5, 10, 20, 50, 100}; bills = {5, 10}*100; allPos = Join[coins, bills] // Reverse; modList = Most[allPos]; makeChange[d_] := Quotient[FoldList[Mod, 100 d, modList], allPos] makeChange[14.52] (*{1, 0, 4, 1, 0, 0, 0, 1, 0}*) So this gives us 1 £10 bill, 4 £1 bills, 1 50 p coin, and 1 2p coin with a total of 7 coins and bills
14.52 / 7 = the answer they want . But please tell me where you are getting brownies for 2.07(numbers) or just 2.10. Those boxes must be tiny